Back to Minimum overlap problem

n = 15
f(x) = 0 for 0x < 2/15
f(x) = 0.09938602for 2/15x < 4/15
f(x) = 0.64299877for 4/15x < 6/15
f(x) = 0.36104582for 6/15x < 8/15
f(x) = 0.69536426for 8/15x < 10/15
f(x) = 0.59241335for 10/15x < 12/15
f(x) = 0.89573331for 12/15x < 14/15
f(x) = 0.92611694for 14/15x ≤ 1
f(x) = f(2-x)for 1< x ≤ 2
Illustration
α(f) < 0.38153155
 maximal for 2/15 ≤ |k| ≤ 12/15
Discovered: May 2010