Back to Minimum overlap problem

n = 19
f(x) = 0 for 0x < 4/19
f(x) = 0.348795091509472207for 4/19x < 6/19
f(x) = 0.742684181900847446for 6/19x < 8/19
f(x) = 0.207655267155520404for 8/19x < 10/19
f(x) = 0.780222086674911898for 10/19x < 12/19
f(x) = 0.568104573396874436for 12/19x < 14/19
f(x) = 0.689049157609512654for 14/19x < 16/19
f(x) = 0.967251286500411737for 16/19x < 18/19
f(x) = 0.892476710504898436for 18/19x ≤ 1
f(x) = f(2-x)for 1< x ≤ 2
Illustration
α(f) < 0.381112263316104816
 maximal for 2/19 ≤ |k| ≤ 16/19
Discovered: May 2010