Back to Minimum overlap problem

n = 35

f(x) = 0		for 0		≤ x < 6/35
f(x) = 0.03238003560575		for 6/35		≤ x < 8/35
f(x) = 0.46469335227746		for 8/35		≤ x < 10/35
f(x) = 1		for 10/35		≤ x < 12/35
f(x) = 0.08179883609036		for 12/35		≤ x < 14/35
f(x) = 0.32969693439226		for 14/35		≤ x < 16/35
f(x) = 0.69700395490768		for 16/35		≤ x < 18/35
f(x) = 0.50267022624400		for 18/35		≤ x < 20/35
f(x) = 0.72207503730147		for 20/33		≤ x < 22/35
f(x) = 0.31005623320619		for 22/35		≤ x < 24/35
f(x) = 0.86664405573480		for 24/35		≤ x < 26/35
f(x) = 0.65866221465766		for 26/35		≤ x < 28/35
f(x) = 0.84471706808832		for 28/35		≤ x < 30/35
f(x) = 0.78739476150616		for 30/35		≤ x < 32/35
f(x) = 0.98857595739413		for 32/35		≤ x < 34/35
f(x) = 0.92726266518752		for 34/35		≤ x ≤ 1
f(x) = f(2-x)		for 1		< x ≤ 2

Illustration
α(f) < 0.38097062715367

maximal for 4/35 ≤ |k| ≤ 30/35

Discovered: May 2011